Question

quais as raízes da equação do 2º grau x^2+14x-13=0?

Answer 1

$x = -14 \sqrt\frac{-14^2 - 4 . 1 . 13}{2.1} } } \\ x = -14 \sqrt{ \frac{196 - 52}{2}} \\ x = -14 \ \sqrt{ \frac{144}{2} } \\x' = \frac{-14 - 12}{2} = -13 \\ x'' = \frac{-14 + 12}{2} = -1 \\S= { -13 , -1 }$