Question

quais as coordenadas do vértice da função y= -x2+6x-8​

Answer 1

Resposta:

y= -x² +6x -8

coeficientes

a=-1

b=6

c= -8

Δ=b² -4ac

Δ=6²-4(-1)(-8)

Δ=36-32

Δ=4

$Xv={-b\over2a}={-6\over2(-1)}={-6\over-2}=3\\ \\ Yv={-\Delta\over4a}={-4\over4(-1)}={-4\over-4}=1\\ \\ V(3,1)$