Question

Q1-se log8(base 10)=a então log5(base 10) vale:
a)a³ b)5a-1 c)2a/3 d)1+ a/3 e)1-a/3
Q2-

Answer 1

$log8=a \Rightarrow log2^3=a \Rightarrow 3log2=a \Rightarrow log2=\frac{a}{3}\\ \\ log5=log(\frac{10}{2})=log10-log2=1-\frac{a}{3}=\frac{1-a}{3}$