Question

purfavor mi ajudem nrstad contad

Answer 1

$a)\ (2-\frac{1}{2})^2.(1-\frac{2}{5})= \\ \\ ( \frac{3}{2})^2.(\frac{3}{5})= \\ \\ \frac{3}{2}. \frac{3}{2}.( \frac{3}{5})= \\ \\ \frac{9}{4}. \frac{3}{5}= \frac{27}{20}$



$b)\ (\frac{3}{4}+ \frac{1}{2}):(1\frac{1}{2}- \frac{3}{4})=\\ \\(\frac{5}{4}):( \frac{3}{2}- \frac{3}{4})=\\ \\ \frac{5}{4}:(\frac{3}{4})= \\ \\ \frac{5}{4}.\frac{4}{3}= \\ \\ \frac{20}{12}= \frac{5}{3}$



$c)\ (1+\frac{3}{7})^2. \frac{49}{80}= \\ \\ (\frac{10}{7})^2. \frac{49}{80}= \\ \\ \frac{10}{7}. \frac{10}{7}. \frac{49}{80}= \\ \\ \frac{100}{49}. \frac{49}{80}= \\ \\ \frac{100}{80}= \frac{5}{4}$



$d)\ [(\frac{2}{5}+ \frac{1}{2}). \frac{2}{9}+(\frac{1}{3})^2]: \frac{7}{5}= \\ \\ \ [(\frac{9}{10}). \frac{2}{9}+\frac{1}{3}.\frac{1}{3}]: \frac{7}{5}= \\ \\ \ [\frac{1}{5}+\frac{1}{9}]: \frac{7}{5}= \\ \\ \ [\frac{14}{45}]: \frac{7}{5}= \\ \\ \frac{14}{45}. \frac{5}{7}= \frac{2}{9}$



$e)\ \sqrt{ \frac{1}{5}.( \frac{2}{5} -2 \frac{1}{2} : \frac{25}{2} }): \frac{1}{5}= \\ \\ \sqrt{ \frac{1}{5}.( \frac{2}{5} - \frac{5}{2} : \frac{25}{2} }): \frac{1}{5}= \\ \\ \sqrt{ \frac{1}{5}.( \frac{2}{5} - \frac{5}{2} . \frac{2}{25} }): \frac{1}{5}=\\\\\sqrt{ \frac{1}{5}.( \frac{2}{5} -\frac{1}{5} }): \frac{1}{5}=\\\\\sqrt{ \frac{1}{5}.(\frac{1}{5} }): \frac{1}{5}=\\\\\sqrt{\frac{1}{25} }: \frac{1}{5}=\\\\\frac{\sqrt1}{\sqrt{25}}:\frac{1}{5}=\\\\\frac{1}{5}:\frac{1}{5}=\\\\\frac{1}{5}.\frac{5}{1}=1$



$f)\ (3 \frac{1}{5} - \frac{1}{5} ):\sqrt{\frac{1}{9}}= \\ \\ (\frac{16}{5} - \frac{1}{5} ):\frac{\sqrt1}{\sqrt9}= \\ \\ (\frac{15}{5}):\frac{1}{3}= \\ \\ (3):\frac{1}{3}=1$