Question

(PUC - RS) O valor numérico de(questão na imagem em anexo)

Answer 1

Resposta:

D

Explicação passo-a-passo:

$\sqrt{\frac{3}{4}-x } +\sqrt{2x} -\frac{3}{2}\sqrt{1-4x} \\ \sqrt{\frac{3}{4}-\frac{1}{12} } +\sqrt{2.\frac{1}{12}} -\frac{3}{2}\sqrt{1-4.\frac{1}{12}} \\\sqrt{\frac{36-4}{48}} +\sqrt{\frac{1}{6}} -\frac{3}{2}\sqrt{1-\frac{1}{3}} \\\sqrt{\frac{32}{48}} +\sqrt{\frac{1}{6}} -\frac{3}{2}\sqrt{\frac{2}{3}} \\ \sqrt{\frac{4}{6}} +\sqrt{\frac{1}{6}} -\frac{3}{2}\sqrt{\frac{2}{3}}\\2\sqrt{\frac{1}{6}} +\sqrt{\frac{1}{6}} -\frac{3}{2}\sqrt{\frac{2}{3}}$

$3\sqrt{\frac{1}{6}} -\frac{3}{2}\sqrt{\frac{2}{3}}\\ 3\sqrt{\frac{1}{6}} -\frac{3}{2}\sqrt{\frac{2.9}{3.4}}\\3\sqrt{\frac{1}{6}} -\sqrt{\frac{9}{6}}\\3\sqrt{\frac{1}{6}} -3\sqrt{\frac{1}{6}}=0$