Question

Puc-PR Em 100 gramas de alumínio, quantos átomos destes elementos estão presentes? Dados: M(AI)= 27 g/mol 1 mol = 6,02 x 1023 atomos

Answer 1

$Ola'~~~~\mathbb{KAROOL} \\ \\ ~~~27g---\ \textgreater \ 1mol---\ \textgreater \ 6,02.10 ^{23}\acute{a}tomos \\ 100g ----------\ \textgreater \ x \\ \\ Por~regra~de~tres~temos: \\ \\ x= \frac{100\not g.(6,02 .10^{23})\acute{a}tomos }{27\not g} \\ \\ x= \frac{100.(6,02. 10^{23}\acute{a}tomos }{27} \\ \\ x=22,2. 10^{23}\acute{a}tomos \\ \\ \boxed{\boxed{x=2,22. 10^{24} ~\acute{a}tomos}}~---\ \textgreater \ \textcircled{d} \\ \\ \\ \mathbb{iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii} \\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$