Question

(PUC) O ponto extremo de f(x) = x² - 6x + 8 é:

Answer 1

Resposta:

V(3,-1)

Explicação passo a passo:

$x_v = \frac{-b}{2a}\\\\x_v= \frac{-(-6)}{2.1} =\frac{6}{2}=3\\\\f(3)=3^2-6.3+8=9-18+8=-1\\\\V(3,-1)$