Question

puc no sistema log x + log y = 1 x^2+y^2=44 x+y é? me ajudeeem por favor!

Answer 1

$\left \{ {{logx+logy=1} \atop {x^2+y^2=44}} \right. \\ \\ \left \{ {{log(xy)=1} \atop {x^2+y^2=44}} \right. \\ \\ \left \{ {{xy=10} \atop {x^2+y^2=44}} \right. \\ \\ (x+y)^2=x^2+y^2+2xy\\ \\ (x+y)^2=44+2*10\\ \\ (x+y)^2=44+20\\ \\ (x+y)^2=64\\ \\ x+y=8$