Question

produtos notaveis (a-2ab)2 e ( 2+x)3​

Answer 1

    $(a-2ab)^2=$

$=a^2-2\times a\times2ab+(2ab)^2=$

$=a^2-2\times2a^2b+2^2(ab)^2=$

$=a^2-4a^2b+4a^2b^2=$

$=4a^2b^2-4a^2b+a^2$

    $(2+x)^3=$

$=(2+x)(2+x)^2=$

$=(2+x)(2^2+2\times2\times x+x^2)=$

$=(2+x)(4+4x+x^2)=$

$=2\times4+2\times4x+2x^2+4x+4x^2+x^3=$

$=8+8x+2x^2+4x+4x^2+x^3=$

$=x^3+2x^2+4x^2+8x+4x+8=$

$=x^3+6x^2+12x+8$

Nota: Usei os casos notáveis  $(a+b)^2=a^2+2ab+b^2$  e  $(a-b)^2=a^2-2ab+b^2$

Answer 2

Resposta:

Explicação passo-a-passo:

A)

(a-2ab)^2

= a^2 - 2.a.2ab + (2ab)^2

= a^2 - 4a^2.b + 4a^2.b^2

B)

= ( 2+x)^3

= (x+2)^2.(x+2)

= (x^2+2.2.x+4).(x+2)

= (X^2+4x+4).(x+2)

= X^3 + 2x^2+4x^2+8x+4x+8

= X^3 + 6x^2 + 12x + 8