Question

PRODUTOS NOTÁVEIS

(3x-5)²
(4x-2)²
(6x-7)²
(10x-1)²
(5x+4)²
(3x+7)²
(8x+6)²
(7x+4)²
(9x+2)
(9x+2)(9x-2)
(10y-5)(10)
(2x+10)(2x-10)

Answer 1

Explicação passo-a-passo:

(3x—5)²

= (3x)²—2•3x•5+5²

= 9x²—30x+25

(4x—2)²

= (4x)²—2•4x•2+2²

= 16x²—16x+4

(6x—7)²

= (6x)²—2•6x•7+7²

= 36x²—84x+49

(10x—1)²

=(10x)²—2•10x•1+1²

= 100x —20x + 1

(5x+4)²

=(5x)²+2•5x•4+4²

=25x+40x+16

(3x+7)²

=(3x)²+2•3x•7+7²

=9x²+42x+49

(9x+2)²

= (9x)²+2•9x•2+2²

= 81x²+36x+4

(9x+2)(9x—2)

=81x²—18x+18x—4

=81x²—4

(10y—5)(10)

=100y—50

(2x+10)(2x—10)

=4x²—20x+20x—100

=4x²—100

Espero ter ajudado bastante!)

Answer 2

(3x-5)² = 9x² - 30x + 25

(4x-2)² = 16x² - 16x + 4

(6x-7)² = 26x² - 84x + 49

(10x-1)² = 100x² - 20x + 1

(5x+4)² = 25x²+ 40x + 16

(3x+7)² = 9x² + 42x + 49

(8x+6)² = 64x² + 96x + 36

(7x+4)² = 49x²+ 56x + 16

(9x+2)² = 81x² + 36x + 4

(9x+2)(9x-2) = 9x² - 4

(10y-5)(10) = 100y - 50

(2x+10)(2x-10) = 4x² - 100

Propriedades usadas:

(a+b)(a-b) = a² - b²

(a ± b)² = a² ± 2ab + b²