Question

Produtos notáveis

(3a+2)(3a-2)=

(a²+5)(a²-5)=

(3-x)²=

(5x-2)²=

(0,7x-5)²=

(x/4-2)²=

(x²/2-5)²=

(3x-5)(5x-3)=

Answer 1

(3a+2)(3a-2)=9a^2 - 4

(a²+5)(a²-5)= a^4 - 25

(3-x)²= 9 - 6x + x^2

(5x-2)²= 25x^2 - 20x + 4

(0,7x-5)²= 0,49x^2 - 7x + 25

(x/4-2)²= x^2/16 - x + 4

(x²/2-5)²= x^2/4 - 5x + 25

(3x-5)(5x-3)= 15x^2 - 9x - 25x + 15 ==> 15x^2 - 34x + 15