Preciso pra hoje por favor:
5(x-4)
(9x2+x+7)(x+3)
(x+2)(x+5)(x+3)
4(5x+2)+3(x+10)
Soluções para a tarefa
Respondido por
2
1.
5x - 5 . 4
5x -20
R: 5x -20
2.
(9x2 + x + 7) (x + 3)
(18 + x +10) (x + 3)
(19x + 7) (x + 3)
19x² + 57x + 7x + 21
R: 19x² + 57x + 7x + 21
3.
(x+2).(x+5).(x+3)
(x² + 5x + 2x + 10) (x + 3)
(x² + 7x + 10) (x + 3)
x³ + 3x² + 7x² + 21x + 10x + 30
x³ + 10x² + 31x + 30
R: x³ + 10x² + 31x + 30
4.
4(5x + 2) + 3(x + 10)
20x + 8 + 3x + 30
23x + 38
R: 23 + 38
5x - 5 . 4
5x -20
R: 5x -20
2.
(9x2 + x + 7) (x + 3)
(18 + x +10) (x + 3)
(19x + 7) (x + 3)
19x² + 57x + 7x + 21
R: 19x² + 57x + 7x + 21
3.
(x+2).(x+5).(x+3)
(x² + 5x + 2x + 10) (x + 3)
(x² + 7x + 10) (x + 3)
x³ + 3x² + 7x² + 21x + 10x + 30
x³ + 10x² + 31x + 30
R: x³ + 10x² + 31x + 30
4.
4(5x + 2) + 3(x + 10)
20x + 8 + 3x + 30
23x + 38
R: 23 + 38
ryanmello03:
Obrigado
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