Question

preciso pra hoje pfffvrrr​

Answer 1

Resposta:

Explicação passo a passo:

$Regras...$

$(a+b)^{2} =a^{2} +2ab+b^{2}$

$(a-b)^{2} =a^{2} -2ab+b^{2}$

$10)$

$(\frac{x}{y} -\frac{y}{x}) ^{2} =(\frac{x}{y} )^{2} -2\:.\:\frac{x}{y} \:.\:\frac{y}{x}+(\frac{y}{x}) ^{2} =\frac{x^{2} }{y^{2} } -2+\frac{y^{2} }{x^{2} }=\frac{x^{2} }{y^{2} } +\frac{y^{2} }{x^{2} } -2$

$11)$

$(\frac{3x}{y}+\frac{2y}{x}) ^{2} =(\frac{3x}{y}) ^{2}+2\:.\:\frac{3x}{y} \:.\:\frac{2y}{x}+(\frac{2y}{x}) ^{2} =\frac{9x^{2} }{y^{2} } +12+\frac{4y^{2} }{x^{2} } =\frac{9x^{2} }{y^{2} }+\frac{4y^{2} }{x^{2} } +12$

$12)$

$(3m^{5}+\frac{2}{3m^{3} }) ^{2} =(3m^{5}) ^{2} +2\:.\:3m^{5}\:.\:(\frac{2}{3m^{3} })+(\frac{2}{3m^{3} }) ^{2} =9m^{10}+4m^{2} +\frac{4}{9m^{6} }$