Question

Preciso por gentileza do memorial do calculo. Obrigado

Answer 1

aplicando o teorema de tales obtemos:

$\frac{BC}{AB}=\frac{DE}{EC}\\\\\frac{30}{16}=\frac{x}{8}\\\\(\frac{30}{16}).8=x\\\\x=\frac{30.8}{16}\\\\x=\frac{30}{2}\\\\x=15$

Logo $DE=15$

aplicando o teorema de pitagoras obtemos:

$CD^{2}=DE^{2}+EC^{2}\\\\y^{2}=15^{2}+8^{2}\\\\y^{2}=225+64\\\\y^{2}=289\\\\y=\sqrt{289}\\\\y=17$

Logo $CD=17$