Matemática, perguntado por graziv1742, 1 ano atrás

preciso para amanha formula de bhaskara
x2+17x+30=0
×2-12x+32=0
x2-7x-60=0
x2-4x-60=0
x2-2x-15=0
x2+7x+12=0
x2-12x+36=0
x2+5x-36=0
x2-13x+36=0
x2+2x-3=0
2x2+x=1
3x2+-2x+1=0
7x-x2-6=0
4x2+12x+9=0
y2=8x-15
y+2y2=4
-x2+2x+3=0
-10x2+20x+30=0
x2-4x+4=0
-2x2+x+10=0

Soluções para a tarefa

Respondido por anabeatriz238
5
*fórmulas:
∆=b²-4.a.c

x' e x" = -b+ou- √∆
2a

fiz as primeiras:

x²+17x+30=0
∆=289-4.1.30=
∆=289-4.30
∆=289-120
∆=169

X'=-17+13/2 = -4/2= -2
X''= -17-13/2= -30/2= -15
X'+X''= -17


x²-12x+32=0
∆=144-4.1.32=
∆=144-128=
∆=16

X'= +12+4/2= 16/2= 8
X''= +12-4/2= 8/2= 4
X'+X''= 12


x²-7x-60=0
∆=49-4.1.-60
∆=49+240
∆=289

X'=7+17/2= 24/2= 12
X"= 7-17/2= -10/2= -5
X'+X"= 7


x²-4x-60=0
∆=16-4.1.-60=
∆=16+240=
∆=256

X'=4+16/2= 20/2= 10
X"=4-16/2= -12/2= -6
X'+X"= 4


x²-2x-15=0
∆=4-4.1.-15=
∆=4+60=
∆=64

X'=2+8/2= 10/2= 5
X"=2-8/2= -6/2= -3
X'+X"= 2


x²+7x+12=0
∆=49-4.1.12=
∆=49-48
∆=1

X'=-7+1/2= -6/2= -3
X"=-7-1/2= -8/2= -4
X'+X"= -7


x²-12x+36=0
∆=144-4.1.36=
∆=144-144=
∆=0

X'=X"= 12+0/2= 12/2= 6


x²+5x-36=0
∆=25-4.1.-36
∆=25+144=
∆=169

X'=-5+13/2= 8/2= 4
X"=-5-13/2= -18/2= -9
X'+X"= -5



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