preciso muito desses cálculos
Soluções para a tarefa
Para matrizes 2x2 podemos usar a regra para obtermos a inversa
X=
a b
c d
X⁻¹= d -b
1/det(X) *
-c a
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A=
3 2
1 1
det=3*1-2*1 = 1
A⁻¹=
1 -2
-1 3
B=
0 1
-3 4
det=0+3=3
B⁻¹=
(1/3) * 4 -1 ==> B⁻¹= 4/3 -1/3
3 0 1 0
A)
A ⁻¹ +B
1 -2 + 0 1 = 1 -1
-1 3 -3 4 -4 7
B)
A ⁻¹ * B=
1 -2 * 0 1 = 0+6 1-8
-1 3 -3 4 0 -9 -1+12
=
6 -7
-9 11
C)
B⁻¹ * A
4/3 -1/3 * 3 2 =4-1/3 8/3-1/3
1 0 1 1 3+0 2+0
=
11/3 7/3
3 2