Question

preciso muito da ajuda de vcs

Answer 1

$\frac{a^2+6a+9}{3}: \frac{a^2-9}{a-3}=\\\\\ \frac{(a+3)(a+3)}{3}: \frac{(a+3)(a-3)}{a-3}=\\\\\frac{(a+3)(a+3)}{3}: \frac{a+3}{1}=\\\\ \frac{(a+3)(a+3)}{3}* \frac{1}{a+3}=\\\\ \frac{(a+3)(a+3)}{3*(a+3)}=\\\\ \frac{a+3}{3}$

Answer 2

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