Question

preciso dos valores de x, por favor
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Answer 1

Resposta:

###logₐ b=log b/log a

log₂ x -logₓ 2 =5/2

log x/log 2 -log 2/log x =5/2

(log x * log x -log 2 * log 2)/(log 2 * log x)=5/2

(log²x-log²2)/(log 2 * log x) =5/2

2*(log²x-log²2) =5(log 2 * log x)

2*(log²x-log²2) =5*log x *log 2

fazendo y=log x

2*(y²-log²2) =5*y*log 2

2y²-5ylog 2 -2log² 2=0

y'=[5log 2 +  √ (25log²2+16log² 2)]/4

y'=[5log 2 +  log 2√41]/4

[5log 2 + log 2*√41  ]/4 = log x

x'= 10^([5log 2 + √41  * log 2  ]/4 )

y'=[5log 2 -  √ (25log²2+16log² 2)]/4

y'=[5log 2 -  √41* log 2]/4

[5log 2 - √41 log 2  ]/4 = log x

x''= 10^([5log 2 - √41 * log 2  ]/4 )