Question

Preciso dos cálculos da questão 02 da imagem. Agradeço.

Answer 1

$sen\theta= \dfrac{cateto\,\,\,oposto}{hipotenusa}\\\\\\cos\theta= \dfrac{cateto\,\,\,adjacente}{hipotenusa}\\\\\\tg\theta= \dfrac{cateto\,\,\,oposto}{cateto\,\,\,adjacente}$

$\overline{AC}\,^2=6^2+8^2\\\\\overline{AC}\,^2=36+64\\\\\overline{AC}\,^2=100\\\\ \boxed {\overline{AC}=10}$

$a)\,\,sen\,\hat{A}= \dfrac{6}{10}\\\\ \boxed{sen\,\hat{A}= \dfrac{3}{5}} =\ \textgreater \ \boxed{sen\,\hat{A}=0,6}$

$b)\,\,cos\,\hat{A}= \dfrac{8}{10}\\\\ \boxed{cos\,\hat{A}= \dfrac{4}{5}} =\ \textgreater \ \boxed{cos\,\hat{A}=0,8}$

$c)\,\,tg\,\hat{A}= \dfrac{6}{8}\\\\ \boxed{tg\,\hat{A}= \dfrac{3}{4}} =\ \textgreater \ \boxed{tg\,\hat{A}=0,75}$

$d)\,\,sen\,\hat{C}= \dfrac{8}{10}\\\\ \boxed{sen\,\hat{C}= \dfrac{4}{5}} =\ \textgreater \ \boxed{sen\,\hat{C}=0,8}$

$e)\,\,cos\,\hat{C}= \dfrac{6}{10}\\\\ \boxed{cos\,\hat{C}= \dfrac{3}{5}} =\ \textgreater \ \boxed{cos\,\hat{C}=0,6}$

$f)\,\,tg\,\hat{C}= \dfrac{8}{6}\\\\ \boxed{tg\,\hat{C}= \dfrac{4}{3}} =\ \textgreater \ \boxed{tg\,\hat{C}=1,3\overline{3}}$