Question

Preciso dos cálculos

Answer 1

Segue a resolução

a)

$2^\frac{1}{3} . 2^\frac{1}{4} + 2^\frac{1}{3} : 2^\frac{1}{4} = 2^\frac{7}{12} + 2^\frac{1}{12} = \sqrt[12]{2^7}  + \sqrt[12]{2}  = \sqrt[12]{128} + \sqrt[12]{2}$

b)

$\frac{3,6.10^4}{10^{-2} . 1,2} + \frac{2,1 . 10^{-2}}{10^{-3} . 0,7} = 3. 10^6 + 3. 10 = 10 . 3(10^5+1) = 10 . 3 (100000+1) = 10.3.100001 = 3000030$