Question

preciso dos cálculos!!!!

1) log5 1 =

2) log3 243 =

3) log32 128=

4) log 4/25 625/16=​

Answer 1

Resposta:

1) 0

2) 5

3) 7/5

4) -1/2

Explicação passo-a-passo:

1) log5 1 =  x

$5^x$ = 1

x = 0

2) log3 243 =  x

$3^x$ = 243

$3^x = 3^5$

x = 5

3) log32 128 =  x

$32^x$ = 128

$(2^5)^x$ = $2^7$

$2^{5x} = 2^7$

5x = 7

x = 7/5

4) log 4/25 625/16=​ x

$(4/25)^x$ = 625/16

$((2/5)^2)^x = (5/2)^4\\(2/5)^{2x} = (2/5)^{-4}$

2x = -4

x = -4/2

x = -1/2

Bons estudos. ;)