Question

Preciso dessa resposta até as 20h, me ajudem

Answer 1

Ok.

$\frac{(n+1)!(m+3)!}{(m+2)!n(n+2)!} =\\ \\\frac{(n+1)!(m+3)(m+2)!}{(m+2)!n(n+2)(n+1)!}=\\ \\\boxed{\boxed{= \frac{(m+3)}{n(n+2)} }}$

Answer 2

(n + 1 ) !       (m + 3 ) !
------------- .   ---------------
( m + 2) !       n ( n + 2) !


( n + 1 ) !     ( m + 3 ) ( m +2) !
--------------  . --------------------------------- simplificando
( m + 2 ) !      n ( n + 2 ) ( n + 1 ) !

1/1 . (m +3) /n (n + 2) = (m + 3 ) / n (n + 2)