Question

preciso de uma ajuda

Answer 1

Faz assim:
6)
(x-1)/(1-X) = 1/2+x/1-x
(x-1)/1-x = (1-x+2x)/(2-2x)
(x-1)/1-x = (1-x)/2-2x
(x-1).(2-2x) = (1+x).(1-x)
2x-2x²-2+2x = (1-x-x+x²)
-2x²-2+4x = 1-2x+x²
-2x²-x²+4x+6x-2-1 = 0
-3x²+10x-3 = 0

7)a)
11/x-4 = 5/x-10
11(x-10) = 5(x-4)
11x-110 = 5x-20
11x-5x = -20+110
6x = 90
x = 90/6
x = 15

b)
7/x-3 = 2/x+2
7(x+2) = 2(x-3)
7x+14 = 2x-6
7x-2x = -6-14
5x = -20
x = -20/5
x = -4

Resposta A) do lado
Δ = √b²-4ac
Δ = √(-3)²-1(1)(2)
Δ = √9-8
Δ = √1
Δ = 1

x = (-b+/-√Δ)/2a
x = (-(-3)+/-√1)/2
x1 = 3+1/2
x1 = 4/2 = 2

x2 = 3-1/2
x2 = 2/2 = 1