Question

preciso de ajuda urgente na nona e na décima alguém?

Answer 1

09. Temos
f(√2/3) = 2(√2/3)² – 3 · √2/3 + 1
f(√2/3) = 2 · 2/9 – √2 + 1
f(√2/3) = 2 · 2/9 – √2 + 1
f(√2/3) = 4/9 – √2 + 1
f(√2/3) = 13/9 – √2
∴ f(√2/3) = (13 – 9√2)/9

10. a) 6 > 5, então
f(6) = 3 · 6 – 20 = –2

b) –1 < 5, então
f(–1) = (–1)² – 2 · (–1) = 1 + 2 = 3

c) 10 > 9, então
f(10) = –10² + 4 · 10 – 2 = –100 + 40 – 4 = –64

d) 9 = 9, então
f(9) = –9² + 4 · 9 – 2 = –81 + 36 – 4 = –49

e) 5 = 5, então
f(5) = 3 · 5 – 20 = –5

f) 0 < 5, então
f(0) = (0)² – 2 · (0) = 0 – 0 = 0

g) 4 < 5, então
f(4) = (4)² – 2 · (4) = 16 – 8 = 8