Question

Preciso de ajuda pfvvvvvvvvvvvvvvvvv rápido

Answer 1

Resposta:

1) dy/dx  = 4x - 13

  dy/dx = -1 => 4x - 13 = -1 => 4x = 12 ∴ x = 3

2)

a) f'(x) = 3x² + 6x

b) f (x) = x² + 2$x^{1/2}$ - $x^{1/3}$

   f'(x) = 2x + $x^{-1/2}$ - $x^{-2/3}$/3

c) f(x) = g(x)/h(x) onde g(x) = 2x² - 1   e h (x) = x +3

[g(x)/h(x)]' = [g'(x).h(x) - g(x).h'(x)] / g(x)² =>

f'(x) = [4x.(x+3) - (2x²-1).1] / (x² + 2x.3 + 9) =>

f'(x) =(4x² + 12x - 2x² +1 ) / x² + 6x +9

f'(x) = (2x² + 12x +1) / (x² + 6x +9)

3.  g (x) = x². f(x)

g'(x) = 2x.f(x) + x².f'(x)  

Explicação passo a passo: