Question

Preciso de ajuda para resolver equacoes biquadradas
x4-8x2+16=0

Answer 1

x^4 -8x² + 16= 0      x²=y
y²-8x + 16=0

Δ= (-8)² -4*1*16
      64 - 64
          0

x= -(-8)/2*1
     8/1
      8     

Answer 2

$x^{4} -8 x^{2} +16=0 x^{2} -8x+16=0 Δ= (-8) x^{2} -4*1*16 Δ= 64-64=0 x= {-(-8) +/- √0} /2 x= (8 +/- 0)/2 x= 0/2 x=0$