Question

Preciso de ajuda nessa matéria

Answer 1

Resposta:

$a)\\ \\ 2-(\frac{1}{5}+ \frac{2}{7} )=\\ \\ mmc=35\\ \\ 2-\frac{7+10}{35} =\\ \\ 2-\frac{17}{35} =\frac{70-10}{35} =\frac{60}{35} =\frac{12}{7} \\ \\ b)\\ \\ (\frac{4}{3} +\frac{7}{2} )-\frac{3}{5} =\\ \\ \frac{8+21}{6} -\frac{3}{5} =\frac{29}{6} -\frac{3}{5} \\ \\ mmc=30\\ \\ \frac{145-18}{30} =\frac{127}{30}$

$c)\\ \\ \frac{1}{2} .(\frac{2}{5} +\frac{3}{4} )=\\ \\ mmc=20\\ \\ \frac{1}{2} .\frac{8+15}{20} =\frac{1}{2} .\frac{23}{20} =\frac{23}{40} \\ \\ d)\\ \\ (\frac{1}{2} +\frac{3}{4} )^{2} =(\frac{1}{2} )^{2} +2.\frac{1}{2} .\frac{3}{4} +(\frac{3}{4} )^{2} =\\ \\ \frac{1}{4} +\frac{6}{8} +\frac{9}{16} =\\ \\ mmc=16\\ \\ \frac{4+12+9}{16} =\frac{25}{16}$

$e)\\ \\ (\frac{7}{5} -\frac{5}{6} )^{2} =(\frac{7}{5} )^{2} -2.\frac{7}{5} .\frac{5}{6} +(\frac{5}{6} )^{2} =\\ \\ \frac{49}{25} -\frac{70}{30} +\frac{25}{36} =\\ \\ \frac{49}{25} -\frac{7}{3} +\frac{25}{36}\\ \\ mmc=900\\ \\ \frac{1764-2100+625}{900} =\frac{289}{900}$

$f)\\ \\ \frac{9}{10} +(\frac{1}{3})^{2} =\frac{9}{10} +\frac{1}{9} \\ \\ mmc=90\\ \\ \frac{81+10}{90} =\frac{91}{90}$