Question

Preciso de ajuda nas questões 1 e 2, por favor!!

Answer 1

$A.\\9^{0,75}=9^{ \frac{3}{4} } = \sqrt[4]{9^3} \\\\\\B.\\ \frac{(5\times10^{-2}\times3\times10^{12})^2}{3\times10^2\times2\times10^{-4}} =\frac{(15\times10^{10})^2}{6\times10^{-2}}=\frac{15^2\times10^{20}}{6\times10^{-2}}\\\\\\\frac{15^2\times10^{20}\times10^{2}}{6}=\frac{(3\times5)^2\times10^{22}}{2\times3}=\frac{3^2\times5^2\times10^{22}}{2\times3}\\\\\\\frac{3\times5^2\times10^{22}}{2}=\frac{75}{2}\times10^{22}$