Question

PRECISO DE AJUDA NA C E D

Answer 1

$c)\ P(3,2) \ \ \ e\ \ \ r:\ y = 6\\\\ h^2=(x_{_{1}}-x_{_{0}})^2+(y_{_{1}}-y_{_{0}})^2\\\\ h^2=(3-0)^2+(2-6)^2\\ h^2=9+16\\ h=\sqrt{25}\\ \boxed{h=5}\\\\\\ d)\ P(3,2)\ \ \ \ e\ \ \ \ r:\ \ x=-1\\\\ h^2=[3-(-1)]^2 + (2-0)^2\\ h^2=(4)^2 + (2)^2\\ h^2=4^2 + 2^2\\\\ h=\not\sqrt{4^{\not2}+2^{\not2}}\\ h=4+2\\ \boxed{h=6}$

Bons estudos!