Question

Preciso de ajuda, me ajudem, resolva as equações:

Answer 1

Letra D:
$3^{4-2x}=9^{2x}$
$3^{4-2x}=(3^2)^{2x}$
$3^{4-2x}=3^{4x}$
$4-2x=4x$
$4=4x+2x$
$4=6x$
$\boxed{x=\frac{6}{4}}$
$\boxed{\boxed{Resposta-D:x=\frac{3}{2}~|ou|~x=1,5}}$

Letra C:
$\boxed{\frac{2^{x+2}}{2^{2x-3}}=(\frac{8}{16})^{5x}}$
$\boxed{\frac{2^{x+2}}{2^{2x-3}}=(\frac{2^{3}}{2^{4}})^{5x}}$
$\boxed{2^{(x+2)-(2x-3)}=(2^{(3-4)})^{5x}}$
$\boxed{2^{(x+2)-(2x-3)}=(2^{-1})^{5x}}$
$\boxed{2^{(x+2)-(2x-3)}=2^{-5x}}$
$(x+2)-(2x-3)=-5x$
$x+2-2x+3=-5x$
$-x+5=-5x$
$-x+5x=-5$
$4x=-5$
$\boxed{\boxed{Resposta-C:x=-\frac{5}{4}~|ou|~x=-0,8}}$