Question

PRECISO DE AJUDA MATRIZES

Answer 1

Resposta:

$\left[\begin{array}{ccc}28&-2\\-29&52\end{array}\right]$

Explicação passo a passo:

$A=\left[\begin{array}{ccc}-3&2\\4&13\end{array}\right]\\\\\\3B=3\left[\begin{array}{ccc}-9&4\\8&-12\end{array}\right]=\left[\begin{array}{ccc}-27&12\\24&-36\end{array}\right]\\\\\\C=\left[\begin{array}{ccc}4&8\\-9&3\end{array}\right]\\\\\\\\A-3B+C\\\\\\\left[\begin{array}{ccc}-3&2\\4&13\end{array}\right]-3\left[\begin{array}{ccc}-9&4\\8&-12\end{array}\right]+\left[\begin{array}{ccc}4&8\\-9&3\end{array}\right]$

$\left[\begin{array}{ccc}-3&2\\4&13\end{array}\right]-\left[\begin{array}{ccc}-27&12\\24&-36\end{array}\right]+\left[\begin{array}{ccc}4&8\\-9&3\end{array}\right]\\\\\\\\\left[\begin{array}{ccc}-3-(-27)+4&2-12+8\\4-24-9&13-(-36)+3\end{array}\right]$

$\left[\begin{array}{ccc}28&-2\\-29&52\end{array}\right]$