Question

preciso de ajuda em matemática


a-)
$2x {}^{2} - 32 = 0$


b-)
$x {}^{2} - 144 = 0$
c-)
$3x {}^{2} - 12 = 0$
d-)
$x {}^{2} - 4x = 0$
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Answer 1

Resposta:

a) x = -4  ou  x = 4

b) x = -12  ou  x = 12

c) x = -2  ou x = 2

d) x = 0  ou  x = 4

Explicação passo-a-passo:

$a)\,\,2x^2-32=0\to 2x^2= 32\to\\\\x^2=16\to x=\pm\sqrt{16}\to\\\\\boxed{x=-4}\,\,ou\,\,\boxed{x=4}$

$b)\,\,x^2-144=0\to x^2=144\to x=\pm\sqrt{144}\to\\\\\boxed{x=-12}\,\,ou\,\,\boxed{x=12}$

$c)\,\,3x^2-12=0\to 3x^2=12\to\\\\x^2 = 4\to x=\pm\sqrt{4}\to\\\\\boxed{x=-2}\,\,ou \,\,\boxed{x=2}$

$d)\,\,x^2-4x=0\to x(x-4)=0\to\\\\\text{Duas Possibilidades:}\\\\\boxed{x=0}\,\,ou\,\,\boxed{x=4}$

É isso!! :)