Question

Preciso de ajuda 6x^2-x-5=0 alguém poderia me ajuda nessa formula de baskara ?
Grata

Answer 1

$6x^2-x-5=0\\\\ a=6;b=-1;c=-5\\\\\\ \Delta=b^2-4az\to \Delta=(-1)^2-4*6*(-5)\to \Delta=1+120\to \Delta=121\\ \\\\x= \frac{-b+- \sqrt{ \Delta} }{2a} \to x= \frac{-(-1)+- \sqrt{ 121} }{2*6} \to x= \frac{1+- 11 }{12} \to\\\\ \\ x'= \frac{1+ 11 }{12} \to x'= \frac{12 }{12} \to x'=1\\\\\\ x''= \frac{1- 11 }{12} \to x''= \frac{-10 }{12} \to x''= \frac{-5}{6} \\\\\\\\ S= (\frac{-5}{6};1)$