Física, perguntado por jkhkjhdkajhsd, 1 ano atrás

Preciso de 20 questões de física do ensino fundamental como velocidade média essas coisas, ah, e as mesmas precisam ser respondidas!

Soluções para a tarefa

Respondido por Usuário anônimo
1
As mais clássicas:

1)
Resposta:
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V = \frac{\Delta S}{\Delta t} = \frac{300}{10} = 30m/s

2)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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5 = \frac{\Delta S}{60}
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\Delta S = 300m

3)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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20 = \frac{\Delta S}{30} 
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\Delta S = 600m

4)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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50 = \frac{100}{\Delta t}
\\\\
\Delta t = 2s

5)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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V = \frac{45}{5}
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V = 9m/s

6)
Resposta: \\\\ 144 = \frac{4320}{\Delta t} \\\\ \Delta t = 30s = 0,5min

7)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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180 = \frac{\Delta S}{5}
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\Delta S = 900m

8)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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5 = \frac{30}{\Delta t}
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\Delta t = 6s

9)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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V = \frac{100}{10} = 10m/s

10)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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V = \frac{100}{50}
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V = 2m/s

11)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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0,5 = \frac{62 \cdot 0,3}{\Delta t}
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\Delta t = 37,2s

12)
Resposta: \\\\ 11 \cdot 3,6 = 39,6km/h \\\\ O \ motorista \ receber\´{a} \ multa

13)
Resposta: \\\\\ 180 \div 3,6 = 50m/s 

14)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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3 \cdot 10^{8} = \frac{6 \cdot 10^{8}}{\Delta t}
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\Delta t = 2s

15)
Resposta:
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V' = \frac{\Delta S}{\Delta t}
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30 = \frac{\Delta S}{2}
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\Delta S = 60km
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V'' = \frac{\Delta S}{\Delta t}
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20 = \frac{60}{\Delta t}
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\Delta t = 3h

16)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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43,9 = \frac{131,7}{\Delta t}
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\Delta t = 3h

17)
Resposta: \\\\ V = \frac{\Delta S}{\Delta t} \\\\ V = \frac{8100}{15 \cdot 60} \\\\ V = 9m/s

18)
Resposta: \\\\ V = \frac{\Delta S}{\Delta t} \\\\ 20 = \frac{436+14}{\Delta t} \\\\ \Delta t = 22,5s

19)
Resposta:
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V = \frac{\Delta S}{\Delta t}
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100 = \frac{\Delta S}{2}
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\Delta S = 200km

20)
A \rightarrow V = \frac{\Delta S}{\Delta t} \Rightarrow 20 = \frac{10.000}{\Delta t} \Rightarrow \Delta t_{A} = 500s
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B \rightarrow V = \frac{\Delta S}{\Delta t} \Rightarrow 50 = \frac{30.000}{\Delta t} \Rightarrow \Delta t_{B} = 600s
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C \rightarrow V = \frac{\Delta S}{\Delta t} \Rightarrow 5 = \frac{1500}{\Delta t} \Rightarrow \Delta t_{C} = 300s
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D \rightarrow V = \frac{\Delta S}{\Delta t} \Rightarrow 30 = \frac{14400}{\Delta t} \Rightarrow \Delta t_{D} = 480s

\text{A via C e a mais vantajosa}
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