Question

Preciso das contas.
10.

Answer 1

a-) $\frac{ab}{3a^2b^2} = \frac{(ab)}{(ab)(3ab)} = \frac{1}{3ab}$

b-) $\frac{x+y}{3x+3y} = \frac{(x+y)}{3(x+y)} = \frac{1}{3}$