Question

preciso da resposta dessa questão!!​

Answer 1

Resposta passo a passo:

A) $x^{2}y^{4}.x^{5}y^{7}=x^{2+5}y^{4+7}=x^{7}y^{11}$

B) $y^{8}z.y^{6}z^{12}=y^{8+6}z^{1+12}=y^{14}z^{13}$

C) $az.az=a^{1+1}z^{1+1}=a^{2}z^{2}$

D) $a^{15}c^{18}.a^{5}c^{2}=a^{15+5}c^{18+2}=a^{20}c^{20}$

E) $4b^{14}g^{8}.9b^{3}g^{7}=4.9.b^{14+3}g^{8+7}=36b^{17}g^{15}$

F) $-6c^{26}h^{19}.(-5c^{12}h^{4})=-6.(-5)c^{26+12}h^{19+4}=30c^{38}h^{23}$

G) $-10n^{8}q.14nq^{10}=-10.14n^{8+1}q^{1+10}=-140n^{9}q^{11}$

H) $-3q^{5}r^{6}.(-3q^{5}r^{6})=-3.(-3)q^{5+5}r^{6+6}=9q^{10}r^{12}$

I) $20d^{17}h^{32}.(-5d^{28}h^{48})=20.(-5)d^{17+28}h^{32+48}=-100d^{45}h^{80}$

J) $-k^{6}l^{8}.6k^{22}l^{3}=-1.6k^{6+22}l^{8+3}=-6k^{28}l^{11}$

K) $2a^{6}b^{3}c^{9}.15a^{8}b^{5}c^{2}=2.15a^{6+8}b^{3+5}c^{9+2}=30a^{14}b^{8}c^{11}$

L) $13t^{9}u^{10}v.8t^{6}u^{4}v^{7}=13.8t^{9+6}u^{10+4}v^{1+7}=104t^{15}u^{14}v^{8}$

M) $-9h^{14}m^{9}z^{7}.11h^{5}m^{11}z^{8}=-9.11h^{14+5}m^{9+11}z^{7+8}=-99h^{19}m^{20}z^{15}$

N) $7k^{3}w^{20}y.(-k^{2}wy)=7.(-1)k^{3+2}w^{20+1}y^{1+1}=-7k^{5}w^{21}y^{2}$

O) $-35j^{6}m^{3}o^{2}.(-2j^{2}m^{2}o^{2})=-35.(-2)j^{6+2}m^{3+2}o^{2+2}=70j^{8}m^{5}o^{4}$

P) $xy^{5}z^{9}.(-x^{9}y^{5}z)=-x^{1+9}y^{5+5}z^{9+1}=-x^{10}y^{10}z^{10}$

Q) $-7h^{3}l^{7}.(-8h^{5}l^{2}n^{2})=-7.(-8)h^{3+5}l^{7+2}n^{2}=56h^{8}l^{9}n^{2}$

R) $40s^{21}w^{34}.(-10s^{7}x^{12})=40.(-10)s^{21+7}w^{34}x^{12}=-400s^{28}w^{34}x^{12}$

S) $pq.(-p^{3}q^{4}).(-p^{6}q^{6}).(-p^{2}q).pq^{7}.(-p^{5}q^{2}).p^{2}q^{4}=-1.-1.-1.-1p^{1+3+6+2+1+5+2}q^{1+4+6+1+7+2+4}=p^{20}q^{25}$

T) $-2a^{8}d^{5}.(-8a^{2}f^{3}).3a^{4}.(-d).(-2f^{6}).ad^{8}f=-2.(-8).3.(-1).(-2)a^{8+2+4+1}d^{5+1+8}f^{3+6+1}=96a^{15}d^{14}f^{10}$