Preciso da resolução deste problema de matemática (2x + 1)(2x + 1) = 8 + 2 (2x + 1)
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Boa tarde Luis!
Solução!
![(2x + 1)(2x + 1) = 8 + 2 (2x + 1)\\\\\\
4 x^{2} +2x+2x+1=8+4x+2\\\\\\
4 x^{2} +4x-4x=8+2-1\\\\\\
4 x^{2} =9\\\\\\\
x^{2} = \dfrac{9}{4} \\\\\\
x= \pm\sqrt{ \dfrac{9}{4} }\\\\\
x=\pm \dfrac{ 3 }{2}](https://tex.z-dn.net/?f=%282x+%2B+1%29%282x+%2B+1%29+%3D+8+%2B+2+%282x+%2B+1%29%5C%5C%5C%5C%5C%5C%0A4+x%5E%7B2%7D+%2B2x%2B2x%2B1%3D8%2B4x%2B2%5C%5C%5C%5C%5C%5C%0A4+x%5E%7B2%7D+%2B4x-4x%3D8%2B2-1%5C%5C%5C%5C%5C%5C%0A4+x%5E%7B2%7D+%3D9%5C%5C%5C%5C%5C%5C%5C%0A+x%5E%7B2%7D+%3D+%5Cdfrac%7B9%7D%7B4%7D+%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cpm%5Csqrt%7B+%5Cdfrac%7B9%7D%7B4%7D+%7D%5C%5C%5C%5C%5C%0Ax%3D%5Cpm+%5Cdfrac%7B+3+%7D%7B2%7D++ "(2x + 1)(2x + 1) = 8 + 2 (2x + 1)\\\\\\
4 x^{2} +2x+2x+1=8+4x+2\\\\\\
4 x^{2} +4x-4x=8+2-1\\\\\\
4 x^{2} =9\\\\\\\
x^{2} = \dfrac{9}{4} \\\\\\
x= \pm\sqrt{ \dfrac{9}{4} }\\\\\
x=\pm \dfrac{ 3 }{2}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
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