Question

Preciso da 9 e da 10 pra ontem 

Answer 1

9)
$10^{-2} =0,01$

B)
$( 0,1)^{3} =0,001$

C)

$10^{-4} =0,0001$

D)

$( 0,1)^{1} =0,1$

R= (D,A,B,C)

10)
a)
$( \frac{-1}{3} + \frac{2}{5}) .( \frac{-6}{7} )=$

$( \frac{-5+6}{15} ). (\frac{-6}{7} )=$

$\frac{1}{15} . \frac{-6}{7} =$

simplifica 6 com 15
$( \frac{1}{5} ).( \frac{-2}{7}) = \frac{-2}{35}$

b)
$\frac{3}{5} +( \frac{-1}{6} ).( \frac{4}{10} )=$

simplifica 4 com 6 depois com10

$\frac{3}{5} +( \frac{-1}{15} )=$

$\frac{3}{5} - \frac{1}{15} = \frac{9-1}{15} = \frac{8}{15}$