Question

PRECISO COM OS CALCULOS

Answer 1

a-
x²-13-4+20-4x=0
Δ=x²-4x+3=0
Δ=b²-4.a.c
Δ=(-4)²-4.1.3
Δ=16-12
Δ=4
-b₊⁻√Δ/2.a
4₊⁻2/2
6/2=3
2/2=1
s{3,1}

b-
2x-3-32x=4x
2x-3-36x=0
-3-34x=0
-34x=3
x=3/34
x=0,088

Answer 2

a) $\frac{ x^{2} - 13}{4} - 1 = x - 5 \\ \frac{ x^{2} - 13 - 4}{4} = \frac{4x - 20}{4} \\ x^{2} - 4x + 3 = 0$

a = 1, b = - 4, c = 3
Δ = b² - 4ac
Δ = (- 4)² -4.1.3 = 16 - 12 = 4
x₁ = - b + √Δ
             2a
x₁ = - (- 4) + √4 = 4 + 2 = 6  = 3
              2.1            2        2
x₂ = - b - √Δ
            2a
x₂ = - (- 4) - √4 = 4 - 2  = 2  = 1
            2.1             2        2
x = 1 ou 3
b)
$\frac{2x - 3}{8} - 4x = \frac{x}{2} \\ \frac{2x - 3 - 32x}{8} = \frac{4x}{8} \\ 34x = 3 \\ x = \frac{3}{34}$