Question

PRECISANDO DE AJUDA!!!OBRIGADA!!

Answer 1

$a) \ log_{\sqrt2}x=4\Rightarrow x=(\sqrt2)^4=4\\ \\ b) \ log_{\frac{1}{6}}x=-\frac{1}{2}\Rightarrow x=(\frac{1}{6})^{-\frac{1}{2}}=6^{\frac{1}{2}}= \sqrt{6}$

Answer 2

$\textbf{24.}$ Determine o valor de x:

$a) \: log_{ \sqrt{2} } \: x = 4 \\ \Leftrightarrow (\sqrt{2} )^4 = x \\ \Leftrightarrow (2^{\frac{1}{2}})^4 = x \\ \Leftrightarrow 2^{ \frac{4}{2}} = x \\ \Leftrightarrow x = 2^2 \\ \Leftrightarrow x = 4$

$b) \: log_{\frac{1}{6} } \: x = - \frac{1}{2} \\ \Leftrightarrow (\frac{1}{6})^{- \frac{1}{2} }= x \\ \Leftrightarrow x = 6^{ \frac{1}{2}} \\ \Leftrightarrow x = \sqrt{6}$