Question

PRA HOJEEE PFV!!
Três retas paralelas são cortadas por duas transversais, determine o valor de x.
(A) 10
(B) 11
(C) 28
(D) 130/3
(E) 20

Answer 1

Resposta:

x=6

\begin{gathered} \frac{5}{3} = \frac{x + 4}{x} \\ 5x = 3(x + 4) \\ 5x = 3x + 12 \\ 5x - 3x = 12 \\ 2x = 12 \\ x = \frac{12}{2} \\ x =6 \end{gathered}

3

5

=

x

x+4

5x=3(x+4)

5x=3x+12

5x−3x=12

2x=12

x=

2

12

x=6

x=6

Answer 2

$\frac{33 - 27}{27} = \frac{2}{x - 2} \\ \frac{6}{27} = \frac{2}{x - 2} \\ 6(x - 2) = 54 \\ 6x - 12 = 54 \\ 6x = 54 + 12 \\ 6x = 66 \\ x = 11$

Letra B