Question

pra hoje!!

coloquem a resolução, por favoor <3

Answer 1

             Expressões trigonométricas

$y=\dfrac{tg420+sec30-cot45}{3-csc90} \\\\\\y=\dfrac{tg(420-360)+\frac{2\sqrt{3} }{3} -1}{3-1} \\\\\\y=\dfrac{tg60+\frac{2\sqrt{3} }{3}-1}{2} \\\\\\y=\dfrac{\sqrt{3} +\frac{2\sqrt{3} }{3}-1}{2}\\\\\\y=\dfrac{\frac{3\sqrt{3} +2\sqrt{3} -3}{3} }{2} \\\\\\\boxed{\bf{y=\dfrac{5\sqrt{3}-3 }{6} }}$

Espero ter ajudado, boa sorte!!