Question

PRA HOJE (11/06)!
Sendo f(x)=x²+3x-2 definida de R em R determine:
a) f(0)
b) f(2)
c) f(-1)
d) f(raíz de 2)
e) f(2/3)
f) f(0,3)

Answer 1

Vamos substituir e determinar.

x² + 3x - 2

a) F(0) = 0 + 0 - 2 = -2

b) F(2) = 4 + 6 -2 = 8

c) F(-1) = (-1)² + 3*(-1) -2 = -4

d) F(√2) = (√2)² + 3√2 - 2
F(√2) = 2 -2 + 3√2
F(√2) = 3√2

e) F(2/3) = (2/3)² + 3(2/3) -2
F(2/3) = 4/9 + 2 -2
F(2/3) 4/9

F) F(0,3) = 0,09 + 0,9 - 2
F(0,3) = 0,99 - 2
F(3) = -0,01


att Jhonny