Question

Pq V2= Vo2+2ad
49=9+2.1.d
=20m??????

Answer 1

$V^{2} = V.^{2} + 2ad$

Se 49=9+2.1.d,

$V^{2}$ = 49

$V = \sqrt{49}$

V = 7 m/s

$V.^{2}$ = 9

$V. = \sqrt{9}$

V = 3 m/s

a = 1 m/s2

49 = 9 + 2.1.d

49 - 9 = 2d

40 = 2*d

d = 40/2

d =20m