Question

Potenciação.
Alguém poderia me ajudar na simplificação dessas expressões?

Answer 1

$\dfrac{\sqrt[3]{0,25}-\sqrt[3]{2} }{\sqrt[3]{2}}=\dfrac{\sqrt[3]{0,25}}{\sqrt[3]{2}}-\dfrac{\sqrt[3]{2}}{\sqrt[3]{2}}=\dfrac{\sqrt[3]{0,25}}{\sqrt[3]{2}}-1$

3)

$1000^{\frac{2}{3}}+\frac{1}{27}^{-\frac{4}{3}}-(625)^{-0.75}=\\\\\\\sqrt[3]{1000^2}+\sqrt[3]{27^4}-(625)^{\frac34}=\\\\\\10^2+3^4-\sqrt[4]{625^3}=\\100+81-5^3=\\100+81-125=156$