Question

Porfavor me ajudem. preciso entregar amanhã.

Transforme numa só potencia:
a - 7^9 x 7^-6 =
b - ( 3 x 10^2)^-1 =
c - 10^-9 x 10 x 10^5 =
d - 6^4 : 6^5 =
e - ( 19^5)^-2 =
f - 2^7 / 2^-2 =
g - ( 5 . 11 ) ^2 =
h - x^11 : x^9 =

se possível expliquem para eu aprender e compreender a fazer.

Answer 1

$a)\\\\7^9~.~7^{-6}~=~7^{9+(-6)}~=~\boxed{7^{3}}\\\\\\b)\\\\\left(3~.~10^2\right)^{-1}~=~\boxed{\frac{1}{3~.~10^2}~~ou~~\frac{1}{300}}\\\\\\c)\\\\10^{-9}~.~10~.~10^5~=~10^{(-9)+1+5}~=~\boxed{10^{-3}~~ou~~\frac{1}{10^3}}\\\\\\d)\\\\6^4:6^5~=~\frac{6^4}{6^5}~=~6^{4-5}~=~\boxed{6^{-1}~~ou~~\frac{1}{6}}\\\\\\e)\\\\\left(19^5\right)^{-2}~=~19^{\,5~.~(-2)}~=~\boxed{19^{-10}~~ou~~\frac{1}{19^{10}}}\\\\\\f)\\\\2^7/2^{-2}~=~\frac{2^7}{2^{-2}}~=~2^{7-(-2)}~=~2^{7+2}~=~\boxed{2^{9}}$

$g)\\\\(5~.~11)^{2}~=~(55)^2~=~\boxed{55^2}\\\\\\h)\\\\x^{11}:x^9~=~\frac{x^{11}}{x^9}~=~x^{11-9}~=~\boxed{x^{2}}$