Question

porfavor a 88888888888

com contaaaaaaaaaaaaaaa

Answer 1

$3x^2-10x+7\\fatorar\ expressao\\\left(3x^2-3x\right)+\left(-7x+7\right)\\3x\left(x-1\right)-7\left(x-1\right)\\=\left(x-1\right)\left(3x-7\right)\\1<x<\frac{7}{3}$

ou

$3x^2-10x+7=0\\\\x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:3\cdot \:7}}{2\cdot \:3}\\\\x_{1,\:2}=\frac{-\left(-10\right)\pm \:4}{2\cdot \:3}\\\\x_1=\frac{-\left(-10\right)+4}{2\cdot \:3},\:x_2=\frac{-\left(-10\right)-4}{2\cdot \:3}\\\\x=\frac{7}{3},\:x=1$

da tabela, a soma dos intervalos:

Encontre os intervalos que satisfaça : < 0

$1<x<\frac{7}{3}$