Matemática, perguntado por emanoelalves239, 3 meses atrás

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Soluções para a tarefa

Respondido por paulodamaia
0

4,6|2

2,3|2

1,3|3

1,1 MMC 2×2×3=12

 \frac{1}{4}  +  \frac{1}{6}  =  \\  \\  \frac{3 + 2}{12}  =  \frac{5}{12}

8,6|2

4,3|2

2,3|2

1,3|3

1,1 MMC 2×2×2×3= 24

 \frac{3}{8}  +  \frac{1}{6}  =  \\  \\  \frac{9 + 4}{24}  =  \frac{13}{24}

6,9|2

3,9|3

1,3|3

1,1 MMC 2×3×3= 18

 \frac{1}{6}  +  \frac{2}{9}  =  \\  \\  \frac{3 + 4}{18}  =  \frac{7}{18}

4,6|2

2,3|2

1,3|3

1,1 MMC 2×2×3= 12

 \frac{3}{4}  +  \frac{1}{6}  =  \\  \\  \frac{9 + 2}{12}  =  \frac{11}{12}

3,4|2

3,2|2

3,1|3

1,1 MMC 2×2×3= 12

 \frac{1}{3}  +  \frac{1}{4}  =  \\  \\  \frac{4 + 3}{12}  =  \frac{7}{12}

2,5|2

1,5|5

1,1 MMC 2×5= 10

 \frac{1}{2}  +  \frac{2}{5}  =  \\  \\  \frac{5 + 4}{10}  =  \frac{9}{10}

3,5|3

1,5|5

1,1 MMC 3×5= 15

 \frac{1}{3}  +  \frac{3}{5}  =  \\  \\  \frac{5 + 9}{15}  =  \frac{14}{15}

4,5|2

2,5|2

1,5|5

1,1 MMC 2×2×5= 20

 \frac{3}{4}  +  \frac{1}{5}  =  \\  \\  \frac{15 + 4}{20}  =  \frac{19}{20}

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