Question

Por qual monômio devemos dividir 2/3a²y³ para obter -1/7ay?

Answer 1

$\frac{ \frac{2}{3} {a}^{2} {y}^{3} }{x} = - \frac{1}{7} ay \\ x = \frac{ \frac{2}{3} {a}^{2} {y}^{3} }{ - \frac{1}{7} ay}$
$x = \frac{2}{3} \times - 7 \times {a}^{2} {y}^{3} {a}^{ - 1} {y}^{ - 1} \\ x = - \frac{14}{3} a {y}^{2} > > > >resposta$