Question

POR FAVOR! urgente :/
a) i(x) = 3(2x - 4) + 2(6 - 3x) =

b) j(x) = 2 +x² - (7 + x + x²) =

c) l(x) = 1/2 (x + 3) - 2x + 3/2 =

Answer 1

a)

$i(x)=3(2x-4)+2(6-3x)=6x-12+12-6x=0$

b)

$j(x)=2+x^2-(7+x+x^2)=2+x^2-7-x-x^2=-x-5$

c)

$l(x)=\frac{1}{2}(x+3)-2x+\frac{3}{2}=\frac{x}{2}+\frac{3}{2}-2x+\frac{3}{2}=-\frac{3x}{2}+3$